Integrand size = 12, antiderivative size = 103 \[ \int (a+b \tan (c+d x))^4 \, dx=\left (a^4-6 a^2 b^2+b^4\right ) x-\frac {4 a b \left (a^2-b^2\right ) \log (\cos (c+d x))}{d}+\frac {b^2 \left (3 a^2-b^2\right ) \tan (c+d x)}{d}+\frac {a b (a+b \tan (c+d x))^2}{d}+\frac {b (a+b \tan (c+d x))^3}{3 d} \]
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Time = 0.12 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3563, 3609, 3606, 3556} \[ \int (a+b \tan (c+d x))^4 \, dx=\frac {b^2 \left (3 a^2-b^2\right ) \tan (c+d x)}{d}-\frac {4 a b \left (a^2-b^2\right ) \log (\cos (c+d x))}{d}+x \left (a^4-6 a^2 b^2+b^4\right )+\frac {b (a+b \tan (c+d x))^3}{3 d}+\frac {a b (a+b \tan (c+d x))^2}{d} \]
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Rule 3556
Rule 3563
Rule 3606
Rule 3609
Rubi steps \begin{align*} \text {integral}& = \frac {b (a+b \tan (c+d x))^3}{3 d}+\int (a+b \tan (c+d x))^2 \left (a^2-b^2+2 a b \tan (c+d x)\right ) \, dx \\ & = \frac {a b (a+b \tan (c+d x))^2}{d}+\frac {b (a+b \tan (c+d x))^3}{3 d}+\int (a+b \tan (c+d x)) \left (a \left (a^2-3 b^2\right )+b \left (3 a^2-b^2\right ) \tan (c+d x)\right ) \, dx \\ & = \left (a^4-6 a^2 b^2+b^4\right ) x+\frac {b^2 \left (3 a^2-b^2\right ) \tan (c+d x)}{d}+\frac {a b (a+b \tan (c+d x))^2}{d}+\frac {b (a+b \tan (c+d x))^3}{3 d}+\left (4 a b \left (a^2-b^2\right )\right ) \int \tan (c+d x) \, dx \\ & = \left (a^4-6 a^2 b^2+b^4\right ) x-\frac {4 a b \left (a^2-b^2\right ) \log (\cos (c+d x))}{d}+\frac {b^2 \left (3 a^2-b^2\right ) \tan (c+d x)}{d}+\frac {a b (a+b \tan (c+d x))^2}{d}+\frac {b (a+b \tan (c+d x))^3}{3 d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.40 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.02 \[ \int (a+b \tan (c+d x))^4 \, dx=\frac {-3 i (a+i b)^4 \log (i-\tan (c+d x))+3 i (a-i b)^4 \log (i+\tan (c+d x))-6 b^2 \left (-6 a^2+b^2\right ) \tan (c+d x)+12 a b^3 \tan ^2(c+d x)+2 b^4 \tan ^3(c+d x)}{6 d} \]
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Time = 0.24 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00
method | result | size |
norman | \(\left (a^{4}-6 a^{2} b^{2}+b^{4}\right ) x +\frac {b^{2} \left (6 a^{2}-b^{2}\right ) \tan \left (d x +c \right )}{d}+\frac {b^{4} \left (\tan ^{3}\left (d x +c \right )\right )}{3 d}+\frac {2 a \,b^{3} \left (\tan ^{2}\left (d x +c \right )\right )}{d}+\frac {2 a b \left (a^{2}-b^{2}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(103\) |
derivativedivides | \(\frac {\frac {b^{4} \left (\tan ^{3}\left (d x +c \right )\right )}{3}+2 a \,b^{3} \left (\tan ^{2}\left (d x +c \right )\right )+6 a^{2} b^{2} \tan \left (d x +c \right )-b^{4} \tan \left (d x +c \right )+\frac {\left (4 a^{3} b -4 a \,b^{3}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (a^{4}-6 a^{2} b^{2}+b^{4}\right ) \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(107\) |
default | \(\frac {\frac {b^{4} \left (\tan ^{3}\left (d x +c \right )\right )}{3}+2 a \,b^{3} \left (\tan ^{2}\left (d x +c \right )\right )+6 a^{2} b^{2} \tan \left (d x +c \right )-b^{4} \tan \left (d x +c \right )+\frac {\left (4 a^{3} b -4 a \,b^{3}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (a^{4}-6 a^{2} b^{2}+b^{4}\right ) \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(107\) |
parallelrisch | \(\frac {b^{4} \left (\tan ^{3}\left (d x +c \right )\right )+3 a^{4} d x -18 a^{2} b^{2} d x +3 b^{4} d x +6 a \,b^{3} \left (\tan ^{2}\left (d x +c \right )\right )+6 \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{3} b -6 \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a \,b^{3}+18 a^{2} b^{2} \tan \left (d x +c \right )-3 b^{4} \tan \left (d x +c \right )}{3 d}\) | \(116\) |
parts | \(a^{4} x +\frac {b^{4} \left (\frac {\left (\tan ^{3}\left (d x +c \right )\right )}{3}-\tan \left (d x +c \right )+\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {2 a \,b^{3} \left (\tan ^{2}\left (d x +c \right )\right )}{d}-\frac {2 a \,b^{3} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}+\frac {6 a^{2} b^{2} \left (\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {2 a^{3} b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(124\) |
risch | \(4 i a^{3} b x -4 i a \,b^{3} x +a^{4} x -6 a^{2} b^{2} x +b^{4} x +\frac {8 i a^{3} b c}{d}-\frac {8 i a \,b^{3} c}{d}-\frac {4 i b^{2} \left (-9 a^{2} {\mathrm e}^{4 i \left (d x +c \right )}+3 b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+6 i a b \,{\mathrm e}^{4 i \left (d x +c \right )}-18 a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+3 b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+6 i a b \,{\mathrm e}^{2 i \left (d x +c \right )}-9 a^{2}+2 b^{2}\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}-\frac {4 a^{3} b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}+\frac {4 a \,b^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) | \(218\) |
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Time = 0.24 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.97 \[ \int (a+b \tan (c+d x))^4 \, dx=\frac {b^{4} \tan \left (d x + c\right )^{3} + 6 \, a b^{3} \tan \left (d x + c\right )^{2} + 3 \, {\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} d x - 6 \, {\left (a^{3} b - a b^{3}\right )} \log \left (\frac {1}{\tan \left (d x + c\right )^{2} + 1}\right ) + 3 \, {\left (6 \, a^{2} b^{2} - b^{4}\right )} \tan \left (d x + c\right )}{3 \, d} \]
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Time = 0.12 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.27 \[ \int (a+b \tan (c+d x))^4 \, dx=\begin {cases} a^{4} x + \frac {2 a^{3} b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{d} - 6 a^{2} b^{2} x + \frac {6 a^{2} b^{2} \tan {\left (c + d x \right )}}{d} - \frac {2 a b^{3} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{d} + \frac {2 a b^{3} \tan ^{2}{\left (c + d x \right )}}{d} + b^{4} x + \frac {b^{4} \tan ^{3}{\left (c + d x \right )}}{3 d} - \frac {b^{4} \tan {\left (c + d x \right )}}{d} & \text {for}\: d \neq 0 \\x \left (a + b \tan {\left (c \right )}\right )^{4} & \text {otherwise} \end {cases} \]
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Time = 0.38 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.10 \[ \int (a+b \tan (c+d x))^4 \, dx=a^{4} x - \frac {6 \, {\left (d x + c - \tan \left (d x + c\right )\right )} a^{2} b^{2}}{d} + \frac {{\left (\tan \left (d x + c\right )^{3} + 3 \, d x + 3 \, c - 3 \, \tan \left (d x + c\right )\right )} b^{4}}{3 \, d} - \frac {2 \, a b^{3} {\left (\frac {1}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right )^{2} - 1\right )\right )}}{d} + \frac {4 \, a^{3} b \log \left (\sec \left (d x + c\right )\right )}{d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 991 vs. \(2 (101) = 202\).
Time = 0.81 (sec) , antiderivative size = 991, normalized size of antiderivative = 9.62 \[ \int (a+b \tan (c+d x))^4 \, dx=\text {Too large to display} \]
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Time = 5.16 (sec) , antiderivative size = 167, normalized size of antiderivative = 1.62 \[ \int (a+b \tan (c+d x))^4 \, dx=\frac {b^4\,{\mathrm {tan}\left (c+d\,x\right )}^3}{3\,d}-\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (b^4-6\,a^2\,b^2\right )}{d}-\frac {\ln \left ({\mathrm {tan}\left (c+d\,x\right )}^2+1\right )\,\left (2\,a\,b^3-2\,a^3\,b\right )}{d}+\frac {\mathrm {atan}\left (\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (-a^2+2\,a\,b+b^2\right )\,\left (a^2+2\,a\,b-b^2\right )}{a^4-6\,a^2\,b^2+b^4}\right )\,\left (-a^2+2\,a\,b+b^2\right )\,\left (a^2+2\,a\,b-b^2\right )}{d}+\frac {2\,a\,b^3\,{\mathrm {tan}\left (c+d\,x\right )}^2}{d} \]
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